Current Dividers

2 in Parallel §

Intuitively there’s twice as much current going to go through than because of half the resistance

The current has to add up to 6A, so the current flowing through has to be 4A because the current flowing through has to be half of and add up to 6A

4A + 2A = 6A

There’s a mathematical way to do this

3+ in Parallel §